(1/2)^4x+1=8^2x+1

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Solution for (1/2)^4x+1=8^2x+1 equation: 



(1/2)^4x+1=8^2x+1

We move all terms to the left:

(1/2)^4x+1-(8^2x+1)=0



Domain of the equation: 2)^4x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)^4x-(8^2x+1)+1=0

We get rid of parentheses

(+1/2)^4x-8^2x-1+1=0

We multiply all the terms by the denominator


(+1-8^2x*2)^4x-1*2)^4x+1*2)^4x=0

Wy multiply elements

-4x^2+(+1-8^2x*2)^4x=0

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